Knowledge Management 2.0 – 1

Knowledge Base Management software is generally used to organize information, and provide the facility to retrieve that data or information in future. The internet has made the use of knowledge bases more common as a resource that provide 24/7 technical support to customers through a company’s website. Most of the corporate companies use online knowledge bases for the maximum customer satisfaction.
In general, a knowledge base is a centralized warehouse for information: a public library, a database of related information about a particular subject. In relation to information technology (IT), a knowledge base is a machine-readable resource for the dissemination of information, generally online or with the capacity to be put online. An integral component of knowledge management systems, a knowledge base is used to optimize information collection, organization, and retrieval for an organization, or for the general public.
An intelligent knowledge base can help an enterprise to save money by reducing the time spent by the employee in their effort to find the required information – among countless possibilities – tax laws or company policies and procedures. As a customer relationship management (CRM) tool, a knowledge base can give customers easy access to information that would otherwise require contact with an organization’s staff; as a rule, this capacity should make the interaction simpler for both the customer and the organization. As a Financial Services management tool, a knowledge base can give financial managers easy access to information about the financial matters of the organization that would otherwise require contact with an organization’s staff. A number of software applications are available that allow finance mangers to manage the finances of the company.
In general, a knowledge base is a dynamic collection of information and sometimes may have capability to learn as a part of an Artificially Intelligent expert system. According to the W3C, the Internet may become a vast and complex global knowledge base known as the Semantic Web in the future.
Salient Features of Knowledge Base Software
Most of the knowledgebase software offers certain features like you can publish and manage your articles, whitepapers, user manuals, and business processes. Some attracting features are;
• Users can get almost all kind of information related to the particular product through knowledge base management software. In case the information about customer’s query is not available in knowledge base, it will provide you an easy alternative to ask your query.
• A fully featured browser based knowledge base
• Knowledge Base Software are Highly searchable
• Repeatable, reusable content through templates, file attachments and mirror categories
• Role based access, full control of users and what they can see
• Unlimited user privileges, full control of users and what they can do
Watch the video related to Knowledge Management
Michael Kull from AMPLIFI presents to Washington DC KM Community. … km knowledge management 2.0 web institute
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About Author
KbLance.com is a PHP Powered Knowledge Base Software that allows users to easily create and maintain a FAQ, documentation system, or complete support knowledge base. For more information . Please check out Kblance website at www.kblance.com
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Total distance / Total Time = Average Velocity
First one:
1000 km at 40km/hr = 25hours
1000 km at 60km/hr = 16.667hours
So 2000km/41.667hours = 48 km/hour
Second one:
40km/hr x 2hrs = 80km
60km/hr x 2hrs = 120km
So 200km / 4 hours = 50 km/hr
a=(vf-v1)/Change of Time
a=(2km/min-1km/m)/2 mins.
a=(1km/min)/2mins
a=0.5km/min^2
However if the question asked you to present your answer in standard format, The cceleration is measuered in m/s^2. You must convert it into m/s
1km/min = 1* 1000 / 60 = 16.7m/s
2km/min = 2*1000/60=33.3m/s
a=(vf-v1)/Change of Time
a=(33.3m/s-16.7m/s)/60seconds
a=0.278m/s^2
OK!
a.
How far total?
(40 * 2) + (60 * 2) = 200 km
How much time total?
2 + 2= 4hr
So the average velocity for the whole trip is:
200km/4hr = 50 km/hr
b.
(100 km * hr/40km) + (100km * hr/60km) =
2 1/2 + 1 2/3… hr =
4 1/6 hr
200 km/ (4 1/6 hr) = 48 km/hr
So, *no*.
EDIT: I really can't stand it when people say *yes* when the answer is *no*.
The force of gravity is given by Fg = Gx m1x m2 /d sqr. Substituting we get:
Fg = 6.67 E-11 x 2.0 E30 x 1.0 / (7.0 E 8)sqr = 2.722 E2 = 272.2 N. Note I used the "E" type notation that is used on TI 83/84 calculators.
Well this is just like sound measurement. First of all you can calculate the amount of energy released from the eq. That would be equal to 2000000*(pi*48000^2)J/s = 1.45 x 10^16 J/s
therefore at a distance of 1km, it would be 1.45 x 10^16 J / (pi*1000^2)sm^2 = 4.61 x 10^9 J/sm^2.
Rate of energy passing through 5km^2 would be (4.61 x 10^9)x(5×1000)^2 = 1.152 x 10^17 Watts = 115200 Tera Watts
Hello,
Let me rewrite the equation.
Do you mean?
d = 0.005s^2 + 0.2s. If so we will put 50 in for d and then solve the equation for s.
So
50 = 0.005s^2 + 0.2s subtract 50 from both sides and we have 0 = 0.005s^2 + 0.2s -50
Now let's use the quadratice formula to find s.
x = [-b +/-sqr(b^2 -4ac)]/(2a) so
x = -0.2 +/- sqr((0.2)^2 -4*0.005*(-50))/(2*0.005)
=(-0.2+/- 1.02)/0.010 = 82M. We don't use the negative value as the distance would be negative.
Check My Math Please!
Hope This Helps!
Must be a Kawasaki so I guess that it's Japanese.
(1)
Total Distance = (1∙0 * 3) + (1∙6 * 5) + (1∙4 * 4) = 16∙6 m
Total time = 3 + 5 + 4 = 12 sec.
Ave. Speed = Distance / time
Ave. Speed = 16∙6/ 12
Ave. Speed = 1∙38….m/s
Ave. Speed ≈ 1∙4 m/s.
(2)
Total Distance = 900 + 220 = 1120 m
Total time = 8∙7*60 + 1∙4*60 = 522 + 84
Total time = 522 + 84
Total time = 606
Ave. Speed = Distance / time
Ave. Speed = 1120 / 606
Ave. Speed = 1∙8481….m/s
Ave. Speed ≈ 1∙85 m/s.
(3)
12,587 = 126 * 10²
(4)
Pt.1 = (0∙0, 9∙0)
Pt. 2 = (10, 81)
Slope = (y2 – y1) / (x2 – x1)
Slope = (81 -9) / (10 – 0)
Slope = 72/ 10
Slope = 7∙2 m/s
(5).
Speed = Distance / time.
Speed = 150 / 3
Speed = 50 km /hr.